Let's see how well it works: $latex i\hbar\frac{\partial}{\partial t}\left|\Psi(t)\right>=H\left|\Psi(t)\right>$ $latex \LaTeX&s=4$
Let's see how well it works: $latex i\hbar\frac{\partial}{\partial t}\left|\Psi(t)\right>=H\left|\Psi(t)\right>$ $latex \LaTeX&s=4$